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Re: [Nagios-devel] Bug and (loosely related) patch: Nagios 3.2.1

Posted: Wed Sep 01, 2010 10:52 am
by Guest
Please resubmit this patch against CVS HEAD, as your previous patch was
already applied. Thanks!


Ethan Galstad


Jochen Bern wrote:
> On 08/29/2010 06:24 PM, Jochen Bern wrote:
>> Sorry for the extra work, but there'll be at least one more update - I
>> used strtok() where I *should* have used my_strsep() from the cgiutils
>
> Next attempt ...
>
> -- Replaced the offending strtok() with some local code ...
> -- ... which also handles the backslash escapes of Nagios 3.x.
> -- Tells "(undefined)" and "(empty)" $ARGn$s apart.
> -- Warns of $ARGn$s with leading or trailing whitespace ...
> -- ... and additionally puts them into "‍...‍" to make
> sure that there'll be *something* displayed with the $ARGn$'s color
> (see the "unused: $ARG5$=" line in the screenshot for an example).
> -- Changed a boatload of "printf(...,some_string);" to
> "printf(...,html_encode(some_string,FALSE));".
>
> The whitespace detection is still not quite finished because I hit a
> snag in the existing code, namely, in cgi/cgiutils.c::url_encode() :
>
>> /* spaces are pluses */
>> else if((char)input[x]> str[y]='+';
>> y++;
>> }
>>
>> /* anything else gets represented by its hex value */
>> else{
>
> Note the " whenever a command contains whitespace *other* than spaces, the
> hyperlink to config.cgi?type=command&expand=... converts it to spaces
> (as seen in $ARG1$ in the screenshot; I currently have the code output
> "[WS]" instead of "[SP]" whenever it sees spaces to obscure the problem).
>
> I would like to get and display the *original* whitespace characters (as
> simulated, by manually changing the URL, for $ARG2$ and $ARG5$ in the
> screenshot), but I don't feel comfortable changing the widely-used
> url_encode() just like that ... any opinions?
>
> Another oddity I noticed: It seems that the command_line's are subject
> to strip(), but not the individual $ARGn$s. As a result, some (!) kinds
> of whitespace get stripped off the end of the *last* $ARGn$, but not the
> others.
>
> Kind regards,
> J. Bern
>
>
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